Optimal. Leaf size=680 \[ -\frac {\sqrt [4]{c} \left (\sqrt {a}+\sqrt {c} x^2\right ) \sqrt {\frac {a+b x^2+c x^4}{\left (\sqrt {a}+\sqrt {c} x^2\right )^2}} \left (6 a^{3/2} \sqrt {c} f-3 \sqrt {a} b \sqrt {c} d+a b f-10 a c d+2 b^2 d\right ) F\left (2 \tan ^{-1}\left (\frac {\sqrt [4]{c} x}{\sqrt [4]{a}}\right )|\frac {1}{4} \left (2-\frac {b}{\sqrt {a} \sqrt {c}}\right )\right )}{6 a^{7/4} \left (b-2 \sqrt {a} \sqrt {c}\right ) \left (b^2-4 a c\right ) \sqrt {a+b x^2+c x^4}}-\frac {\sqrt {c} x \sqrt {a+b x^2+c x^4} \left (12 a^2 c f+a b^2 f-16 a b c d+2 b^3 d\right )}{3 a^2 \left (b^2-4 a c\right )^2 \left (\sqrt {a}+\sqrt {c} x^2\right )}+\frac {x \left (c x^2 \left (12 a^2 c f+a b^2 f-16 a b c d+2 b^3 d\right )+4 a^2 b c f+20 a^2 c^2 d+a b^3 f-17 a b^2 c d+2 b^4 d\right )}{3 a^2 \left (b^2-4 a c\right )^2 \sqrt {a+b x^2+c x^4}}+\frac {\sqrt [4]{c} \left (\sqrt {a}+\sqrt {c} x^2\right ) \sqrt {\frac {a+b x^2+c x^4}{\left (\sqrt {a}+\sqrt {c} x^2\right )^2}} \left (12 a^2 c f+a b^2 f-16 a b c d+2 b^3 d\right ) E\left (2 \tan ^{-1}\left (\frac {\sqrt [4]{c} x}{\sqrt [4]{a}}\right )|\frac {1}{4} \left (2-\frac {b}{\sqrt {a} \sqrt {c}}\right )\right )}{3 a^{7/4} \left (b^2-4 a c\right )^2 \sqrt {a+b x^2+c x^4}}+\frac {x \left (c x^2 (b d-2 a f)-a b f-2 a c d+b^2 d\right )}{3 a \left (b^2-4 a c\right ) \left (a+b x^2+c x^4\right )^{3/2}}+\frac {4 \left (b+2 c x^2\right ) (2 c e-b g)}{3 \left (b^2-4 a c\right )^2 \sqrt {a+b x^2+c x^4}}-\frac {-2 a g+x^2 (2 c e-b g)+b e}{3 \left (b^2-4 a c\right ) \left (a+b x^2+c x^4\right )^{3/2}} \]
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Rubi [A] time = 0.51, antiderivative size = 680, normalized size of antiderivative = 1.00, number of steps used = 9, number of rules used = 8, integrand size = 32, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.250, Rules used = {1673, 1178, 1197, 1103, 1195, 1247, 638, 613} \[ \frac {x \left (c x^2 \left (12 a^2 c f+a b^2 f-16 a b c d+2 b^3 d\right )+4 a^2 b c f+20 a^2 c^2 d-17 a b^2 c d+a b^3 f+2 b^4 d\right )}{3 a^2 \left (b^2-4 a c\right )^2 \sqrt {a+b x^2+c x^4}}-\frac {\sqrt {c} x \sqrt {a+b x^2+c x^4} \left (12 a^2 c f+a b^2 f-16 a b c d+2 b^3 d\right )}{3 a^2 \left (b^2-4 a c\right )^2 \left (\sqrt {a}+\sqrt {c} x^2\right )}-\frac {\sqrt [4]{c} \left (\sqrt {a}+\sqrt {c} x^2\right ) \sqrt {\frac {a+b x^2+c x^4}{\left (\sqrt {a}+\sqrt {c} x^2\right )^2}} \left (6 a^{3/2} \sqrt {c} f-3 \sqrt {a} b \sqrt {c} d+a b f-10 a c d+2 b^2 d\right ) F\left (2 \tan ^{-1}\left (\frac {\sqrt [4]{c} x}{\sqrt [4]{a}}\right )|\frac {1}{4} \left (2-\frac {b}{\sqrt {a} \sqrt {c}}\right )\right )}{6 a^{7/4} \left (b-2 \sqrt {a} \sqrt {c}\right ) \left (b^2-4 a c\right ) \sqrt {a+b x^2+c x^4}}+\frac {\sqrt [4]{c} \left (\sqrt {a}+\sqrt {c} x^2\right ) \sqrt {\frac {a+b x^2+c x^4}{\left (\sqrt {a}+\sqrt {c} x^2\right )^2}} \left (12 a^2 c f+a b^2 f-16 a b c d+2 b^3 d\right ) E\left (2 \tan ^{-1}\left (\frac {\sqrt [4]{c} x}{\sqrt [4]{a}}\right )|\frac {1}{4} \left (2-\frac {b}{\sqrt {a} \sqrt {c}}\right )\right )}{3 a^{7/4} \left (b^2-4 a c\right )^2 \sqrt {a+b x^2+c x^4}}+\frac {x \left (c x^2 (b d-2 a f)-a b f-2 a c d+b^2 d\right )}{3 a \left (b^2-4 a c\right ) \left (a+b x^2+c x^4\right )^{3/2}}+\frac {4 \left (b+2 c x^2\right ) (2 c e-b g)}{3 \left (b^2-4 a c\right )^2 \sqrt {a+b x^2+c x^4}}-\frac {-2 a g+x^2 (2 c e-b g)+b e}{3 \left (b^2-4 a c\right ) \left (a+b x^2+c x^4\right )^{3/2}} \]
Antiderivative was successfully verified.
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Rule 613
Rule 638
Rule 1103
Rule 1178
Rule 1195
Rule 1197
Rule 1247
Rule 1673
Rubi steps
\begin {align*} \int \frac {d+e x+f x^2+g x^3}{\left (a+b x^2+c x^4\right )^{5/2}} \, dx &=\int \frac {d+f x^2}{\left (a+b x^2+c x^4\right )^{5/2}} \, dx+\int \frac {x \left (e+g x^2\right )}{\left (a+b x^2+c x^4\right )^{5/2}} \, dx\\ &=\frac {x \left (b^2 d-2 a c d-a b f+c (b d-2 a f) x^2\right )}{3 a \left (b^2-4 a c\right ) \left (a+b x^2+c x^4\right )^{3/2}}+\frac {1}{2} \operatorname {Subst}\left (\int \frac {e+g x}{\left (a+b x+c x^2\right )^{5/2}} \, dx,x,x^2\right )-\frac {\int \frac {-2 b^2 d+10 a c d-a b f-3 c (b d-2 a f) x^2}{\left (a+b x^2+c x^4\right )^{3/2}} \, dx}{3 a \left (b^2-4 a c\right )}\\ &=\frac {x \left (b^2 d-2 a c d-a b f+c (b d-2 a f) x^2\right )}{3 a \left (b^2-4 a c\right ) \left (a+b x^2+c x^4\right )^{3/2}}-\frac {b e-2 a g+(2 c e-b g) x^2}{3 \left (b^2-4 a c\right ) \left (a+b x^2+c x^4\right )^{3/2}}+\frac {x \left (2 b^4 d-17 a b^2 c d+20 a^2 c^2 d+a b^3 f+4 a^2 b c f+c \left (2 b^3 d-16 a b c d+a b^2 f+12 a^2 c f\right ) x^2\right )}{3 a^2 \left (b^2-4 a c\right )^2 \sqrt {a+b x^2+c x^4}}+\frac {\int \frac {-a c \left (b^2 d-20 a c d+8 a b f\right )-c \left (2 b^3 d-16 a b c d+a b^2 f+12 a^2 c f\right ) x^2}{\sqrt {a+b x^2+c x^4}} \, dx}{3 a^2 \left (b^2-4 a c\right )^2}-\frac {(2 (2 c e-b g)) \operatorname {Subst}\left (\int \frac {1}{\left (a+b x+c x^2\right )^{3/2}} \, dx,x,x^2\right )}{3 \left (b^2-4 a c\right )}\\ &=\frac {x \left (b^2 d-2 a c d-a b f+c (b d-2 a f) x^2\right )}{3 a \left (b^2-4 a c\right ) \left (a+b x^2+c x^4\right )^{3/2}}-\frac {b e-2 a g+(2 c e-b g) x^2}{3 \left (b^2-4 a c\right ) \left (a+b x^2+c x^4\right )^{3/2}}+\frac {4 (2 c e-b g) \left (b+2 c x^2\right )}{3 \left (b^2-4 a c\right )^2 \sqrt {a+b x^2+c x^4}}+\frac {x \left (2 b^4 d-17 a b^2 c d+20 a^2 c^2 d+a b^3 f+4 a^2 b c f+c \left (2 b^3 d-16 a b c d+a b^2 f+12 a^2 c f\right ) x^2\right )}{3 a^2 \left (b^2-4 a c\right )^2 \sqrt {a+b x^2+c x^4}}+\frac {\left (\sqrt {c} \left (2 b^3 d-16 a b c d+a b^2 f+12 a^2 c f\right )\right ) \int \frac {1-\frac {\sqrt {c} x^2}{\sqrt {a}}}{\sqrt {a+b x^2+c x^4}} \, dx}{3 a^{3/2} \left (b^2-4 a c\right )^2}-\frac {\left (\sqrt {c} \left (2 b^3 d-16 a b c d+a b^2 f+12 a^2 c f+\sqrt {a} \sqrt {c} \left (b^2 d-20 a c d+8 a b f\right )\right )\right ) \int \frac {1}{\sqrt {a+b x^2+c x^4}} \, dx}{3 a^{3/2} \left (b^2-4 a c\right )^2}\\ &=\frac {x \left (b^2 d-2 a c d-a b f+c (b d-2 a f) x^2\right )}{3 a \left (b^2-4 a c\right ) \left (a+b x^2+c x^4\right )^{3/2}}-\frac {b e-2 a g+(2 c e-b g) x^2}{3 \left (b^2-4 a c\right ) \left (a+b x^2+c x^4\right )^{3/2}}+\frac {4 (2 c e-b g) \left (b+2 c x^2\right )}{3 \left (b^2-4 a c\right )^2 \sqrt {a+b x^2+c x^4}}+\frac {x \left (2 b^4 d-17 a b^2 c d+20 a^2 c^2 d+a b^3 f+4 a^2 b c f+c \left (2 b^3 d-16 a b c d+a b^2 f+12 a^2 c f\right ) x^2\right )}{3 a^2 \left (b^2-4 a c\right )^2 \sqrt {a+b x^2+c x^4}}-\frac {\sqrt {c} \left (2 b^3 d-16 a b c d+a b^2 f+12 a^2 c f\right ) x \sqrt {a+b x^2+c x^4}}{3 a^2 \left (b^2-4 a c\right )^2 \left (\sqrt {a}+\sqrt {c} x^2\right )}+\frac {\sqrt [4]{c} \left (2 b^3 d-16 a b c d+a b^2 f+12 a^2 c f\right ) \left (\sqrt {a}+\sqrt {c} x^2\right ) \sqrt {\frac {a+b x^2+c x^4}{\left (\sqrt {a}+\sqrt {c} x^2\right )^2}} E\left (2 \tan ^{-1}\left (\frac {\sqrt [4]{c} x}{\sqrt [4]{a}}\right )|\frac {1}{4} \left (2-\frac {b}{\sqrt {a} \sqrt {c}}\right )\right )}{3 a^{7/4} \left (b^2-4 a c\right )^2 \sqrt {a+b x^2+c x^4}}-\frac {\sqrt [4]{c} \left (2 b^3 d-16 a b c d+a b^2 f+12 a^2 c f+\sqrt {a} \sqrt {c} \left (b^2 d-20 a c d+8 a b f\right )\right ) \left (\sqrt {a}+\sqrt {c} x^2\right ) \sqrt {\frac {a+b x^2+c x^4}{\left (\sqrt {a}+\sqrt {c} x^2\right )^2}} F\left (2 \tan ^{-1}\left (\frac {\sqrt [4]{c} x}{\sqrt [4]{a}}\right )|\frac {1}{4} \left (2-\frac {b}{\sqrt {a} \sqrt {c}}\right )\right )}{6 a^{7/4} \left (b^2-4 a c\right )^2 \sqrt {a+b x^2+c x^4}}\\ \end {align*}
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Mathematica [F] time = 0.00, size = 0, normalized size = 0.00 \[ \text {\$Aborted} \]
Verification is Not applicable to the result.
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fricas [F] time = 0.96, size = 0, normalized size = 0.00 \[ {\rm integral}\left (\frac {\sqrt {c x^{4} + b x^{2} + a} {\left (g x^{3} + f x^{2} + e x + d\right )}}{c^{3} x^{12} + 3 \, b c^{2} x^{10} + 3 \, {\left (b^{2} c + a c^{2}\right )} x^{8} + {\left (b^{3} + 6 \, a b c\right )} x^{6} + 3 \, a^{2} b x^{2} + 3 \, {\left (a b^{2} + a^{2} c\right )} x^{4} + a^{3}}, x\right ) \]
Verification of antiderivative is not currently implemented for this CAS.
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giac [F] time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {g x^{3} + f x^{2} + e x + d}{{\left (c x^{4} + b x^{2} + a\right )}^{\frac {5}{2}}}\,{d x} \]
Verification of antiderivative is not currently implemented for this CAS.
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maple [B] time = 0.06, size = 1395, normalized size = 2.05 \[ \text {result too large to display} \]
Verification of antiderivative is not currently implemented for this CAS.
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maxima [F] time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {g x^{3} + f x^{2} + e x + d}{{\left (c x^{4} + b x^{2} + a\right )}^{\frac {5}{2}}}\,{d x} \]
Verification of antiderivative is not currently implemented for this CAS.
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mupad [F] time = 0.00, size = -1, normalized size = -0.00 \[ \int \frac {g\,x^3+f\,x^2+e\,x+d}{{\left (c\,x^4+b\,x^2+a\right )}^{5/2}} \,d x \]
Verification of antiderivative is not currently implemented for this CAS.
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sympy [F(-1)] time = 0.00, size = 0, normalized size = 0.00 \[ \text {Timed out} \]
Verification of antiderivative is not currently implemented for this CAS.
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